how many grams of Calcium Carbonate are needed to produce 280g of Calcium Oxide ???? plz help
2007-09-17 07:41:36 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
it depends on the weather.
2007-09-17 07:48:51 · answer #1 · answered by savs 6 · 0⤊ 1⤋
2
2007-09-17 07:43:48 · answer #2 · answered by -___- 1 · 0⤊ 1⤋
Start by writing the balanced chemical equation for the reaction involved. I think it will be:
CaCO3 --> CaO + CO2
So, you have a 1:1:1 molar ratio of all the components.
Now, use the molar mass of calcium oxide to convert 280 g into moles. Since everything happens in a 1:1 molar ratio. that number will be the number of moles of calcium carbonate you need. Finally use the molar mass of CaCO3 to calculate the mass of that number of moles.
You can do the calculations.
2007-09-17 07:49:24 · answer #3 · answered by hcbiochem 7 · 2⤊ 0⤋
find out molar masses of each.
take 280g/molar mas of calcium oxide = moles calcium oxide.
write the equation for the reaction to establish a ratio of reactant to product.
multiply the moles * the ratio = moles of required reactant
moles required * g/mol Calcium carbonate = g required
now just substitute in the valvues and punch in your calculator
2007-09-17 07:49:41 · answer #4 · answered by billgoats79 5 · 1⤊ 0⤋
CaCO3 --> CaO
1 mole of CaCo3 needed to produce 1 mole of CaO
All you need to do is determine the molecular weights of CaCO3 and CaO
280g / X gm/mole = moles of CaO
moles of CaO x Y gm/mole of CaCO3 = grams of CaCO3
2007-09-17 07:53:45 · answer #5 · answered by skipper 7 · 0⤊ 0⤋
The ans = 500grams
2007-09-17 07:50:52 · answer #6 · answered by platz 2 · 1⤊ 0⤋