What is the molality of a solution consisting of 3.03 mL of carbon tetrachloride (CCl4, d = 1.59 g/mL) in 83.5

Question

83.5 mL of methylene chloride (CH2Cl2, d = 1.33 g/mL)?

83.5 mL of methylene chloride (CH2Cl2, d = 1.33 g/mL)?

Answer 1

You need to write the complete question. Without the rest of the question, no one can help you solve it.

I'll start, though, by suggesting that you calculate the number of moles of CCl4. You've got a volume and a density, so you can calculate the mass of CCl4. Using its molar mass, you can calculate the number of moles CCl4 present. Since the definition of molarity is moles solute/L of solution, you might be able to go from there...

Good luck.