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1) A charge of 0.821 nC is placed at the origin. Another charge of 0.395 nC is placed at x1 = 12.9 cm on the x-axis


At which point on the x-axis does this potential have a minimum?


i dont get how to do this problem

2007-09-17 06:22:20 · 2 answers · asked by chs_soccer_02 2 in Science & Mathematics Physics

2 answers

Force is derivative of potential.
Potential has minimum at point, where net electric field is zero.

E(x) = q0/x² - q1/(x1-x)² = 0
q0/x² - q1/(x1-x)² = 0
q0/x² = q1/(x1-x)²
q0(x1-x)² = q1x²
√q0 (x1-x) = √q1 x
√q0 x1 = (√q0 + √q1) x


Answer:
x = x1/(1 + √(q1/q0))

2007-09-17 06:31:50 · answer #1 · answered by Alexander 6 · 0 0

Calculate the electric field intensity from each charge (note that when you are -between- the charges that the fields from each charge point in opposite directions). Now calculate the point between charges where the fields have the same strength but opposite direction. This is the field minimum (the point that an electron would 'feel' a net zero force)

Doug

2007-09-17 13:34:38 · answer #2 · answered by doug_donaghue 7 · 0 0

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