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2007-09-17 03:30:26 · 1 answers · asked by jessica d 1 in Science & Mathematics Chemistry

1 answers

If the reducing agent is lithioum alluminum hydride, LiAlH4, then both benzamide, C6H5-CONH2, and benzonitrile, C6H5-CN, would give benzylamine, C6H5-CH2NH2. A substituted amide like acetanilide, C6H5-NHCO-CH3, would give ethylbenzylamine, C6H5-CH2-NH-CH2CH3.

2007-09-17 03:45:36 · answer #1 · answered by steve_geo1 7 · 0 0

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