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Two crewmen pull a boat through a lock. One crewman pulls with a force of F1 = 105 N at an angle of = 33° relative to the forward direction of the raft. The second crewman, on the opposite side of the lock, pulls at an angle of 45°. With what force F2 should the second crewman pull so that the net force of the two crewmen is in the forward direction?

2007-09-17 02:45:33 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Look at the lateral values
sin(33)*105=F2*sin(45)
F2=80.9 N

j

2007-09-17 05:07:50 · answer #1 · answered by odu83 7 · 0 0

i dont quite agree with top contributor

resolve the forces horizontally,
105cos33>Fcos45
88.06> 0.7071F
F<124.5N

F2 has to be less than 124.5N for a forward direction to be achieved.

2007-09-21 01:46:42 · answer #2 · answered by justjoshua18 3 · 0 0

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