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solve the equation 2^1-x=4^x

2007-09-17 00:47:54 · 4 answers · asked by Anthony 3 in Science & Mathematics Mathematics

4 answers

2 ^ (1 - x ) = ( 2 ² ) ^ x
2 ^ ( 1 - x ) = 2 ^ ( 2 x )
1 - x = 2 x
3 x = 1
x = 1 / 3

2007-09-17 02:05:09 · answer #1 · answered by Como 7 · 2 0

2^1 - x = (2^2)^x
2^1 - x = 2^2x
1 - x = 2x
1 = 2x + x
1 = 3x
x = 1/3

2007-09-17 08:01:06 · answer #2 · answered by doongdoong 1 · 1 0

if you mean 2^(1-x)=4^x, then
2^(1-x)=2^(2x)
therefore
1-x=2x
1=2x+x
1=3x
x=1/3

2007-09-17 08:03:39 · answer #3 · answered by anna t 1 · 1 0

1/3....just coz the other two said so..

2007-09-17 08:29:12 · answer #4 · answered by Anonymous · 0 0

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