A triangle has sides of length x inches, x + 1 inches, and x + 2 inches and its perimeter is given by x + (x + 1) + (x + 2) = 42 inches.
2007-09-16 22:43:59 · 8 answers · asked by Vonnie 2 in Science & Mathematics ➔ Mathematics
3x + 3 = 42
3x = 39
x = 13
Sides are 13 ,14 and 15 ins
2007-09-17 04:48:07 · answer #1 · answered by Como 7 · 2⤊ 0⤋
so what is the question? if you want to look for the length of each side of the triangle then with the given length of x inches, x + 1 inches and x + 2 inches and a perimeter of 42 inches,
The length of side x is :
Perimeter = x + (x + 1)inches + ( x +2) inches = 42 inches
x + x + 1 + x +2 = 42 inches
3x + 3 inches = 42 inches
3x = 42 - 3 inches
3x = 39 inches
x = 13 inches; which length of one sideTo solve for the other two sides:
x + 1 = 13 + 1 = 14 inches
x + 2 = 13 + 2 = 15 inches
Now, we have the length of the three sides of the triangle which are 13, 14, and 15 inches.
2007-09-16 23:05:38 · answer #2 · answered by hayaku_raven22 2 · 0⤊ 0⤋
if you have to find x then the solution would be:
x + (x + 1) + (x + 2) = 42
=> 3x + 3 = 42
=> 3x = 42 - 3
=> 3x = 39
=> x = 13
so the sides are:
x = 13
x + 1 =14
x + 2 = 15
2007-09-16 23:12:02 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x + x + 1 + x +2 = 42
combined similar terms.:
3x + 3 = 42
move 3 to the other side:
3x = 42 - 3
3x = 39 divide both sides by 3
x = 13
x+1 = 14
x+2 = 15
2007-09-16 23:34:54 · answer #4 · answered by Zenaida T 1 · 0⤊ 0⤋
x + x + 1 + x + 2 = 42
3x + 3 = 42
3x = 39
x = 13
2007-09-16 23:05:17 · answer #5 · answered by Si semut 4 · 0⤊ 0⤋
13 , 14 , 15
2007-09-16 22:56:52 · answer #6 · answered by K1998 2 · 0⤊ 0⤋
3x+3 = 42
x = 39/3 = 13
so sides are 13,14,15
2007-09-16 22:49:48 · answer #7 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
x+(x+1)+(x+2)=42
3x+3=42
3x=42-3
3x=39
x=13------ answer
2007-09-16 22:50:16 · answer #8 · answered by Anonymous · 0⤊ 0⤋