Question 1
17 , 19 , 23 , 29 , 31 , 37 , 41 , 43
Question 2
LCM = 40
Question 3
HCF = 4
2007-09-17 03:10:19
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answer #1
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answered by Como 7
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1. A number can only be called Prime number if its divisor are only 1 and itself. And the only even number that is also a prime number is 2. So prime # between 15 and 45 are 17, 19, 23, 29, 31, 37, 41,and 43.
2. L.C.M. of 4, 5, and 8 is:
4 - 4, 8, 12, 16, 20, 24, 28, 32, 36, 40
5 - 5, 10, 15, 20, 25, 30, 35, 40
8 - 8, 16, 24, 32, 40
So the L.C.M. for 4, 5, and 8 is 40.
3. The H.C.F. for 24, 36, and 40 is:
24 - 1, 2, 3, 4, 6, 8, 12, 24
36 - 1, 2, 3, 4, 6, 9, 12, 18, 36
40 - 1, 2, 4, 5, 8, 10, 20, 40
So the H.C.F. for 24, 36, and 40 is 4.
2007-09-16 23:20:19
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answer #2
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answered by hayaku_raven22 2
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1 ) 17 19 23 29 31 37 41 43
2 ) 40
3 ) 4
2007-09-16 22:59:42
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answer #3
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answered by K1998 2
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80 pence situations a million/4 potential 80 situations a million then divided via 4. that's 20. so as that's what he spends. He has left what he had minus what he spends so 80 - 20 = 60 If 24 out of sixty 4 do no longer positioned on glasses so sixty 4 -24 = 40 do positioned on glasses. 40 divided via sixty 4 is the fraction =40/sixty 4 yet 8 is a undemanding ingredient of sixty 4 and 40 so dividing the actual and backside via 8 provides = 5/8
2016-11-15 10:42:27
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answer #4
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answered by deily 4
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The prime nos are 17,19,23,29, 31,37,43,41
2. The lcm of 4 and 8 is 8.Then find the lcm of 8 and 5 which is 40.
3. the highest common factor of 24,36 and 40 is 4. The biggest number that can divide them is 4
2007-09-16 23:04:35
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answer #5
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answered by meeta1704 2
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Pathetic. Truly freaking pathetic.
Learn to count, moron.
Spend less time on Yahoo and more time studying!
BTW, wait until you get into difficult fractions.
2007-09-16 22:55:38
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answer #6
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answered by wroockee 4
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Are you in K.G?Well I have nothing to do with it and the answers are:
1) 17,19,23,29,31,37, 41,43
2) 40
3) 04
2007-09-16 23:25:54
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answer #7
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answered by Anonymous
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1) 17,19,23,29,31,37,41,43
2) 40 is the lcm
3) 4 is the hcf
2007-09-16 22:52:30
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answer #8
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answered by Anonymous
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