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2007-09-16 21:46:39 · 2 answers · asked by sandy 1 in Science & Mathematics Mathematics

we have to proove that in sets and relations prooving that using diagramsis very easy

2007-09-16 22:23:40 · update #1

2 answers

(A U B) - (A ∩ C)

= (A U B) - (A ∩ ~B)

= [A + B - (A ∩ B)] - (A ∩ ~B)

= A + B - [(A ∩ B) + (A ∩ ~B)]

= A + B - A

= B

2007-09-16 22:52:51 · answer #1 · answered by Northstar 7 · 0 0

That's very easy to show with a diagram, but that's very hard to do with a text interface. Get pencil a paper and follow me.

Draw two circles which partially overlap. One circle represents A, the other B. The bit in the middle is AnB. The bit on the left is A-B, on the right is B-A.

Now An(~B) = A-B, the bit on the left. AuB is all three bits together. So (AuB) - (A-B) is all three bits take away the bit on the left.

What you have left is two parts that together make up B.

2007-09-16 22:02:07 · answer #2 · answered by Raichu 6 · 0 0

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