rectangle problem?

Question

A farmer wishes to enclose a rectangular region bordering a river using 600 feet of fencing. He wants to divide the region into two equal parts using some of the fence material. What is the maximum area that can be enclosed with the fencing?

Answer 1

3W + L = 600
A = WL
L = 600 - 3W
A = 600W - 3W^2
A = - 3(W^2 - 200W)
A = - 3(W^2 - 200W + 100^2) + 3(100^2)
A = - 3(W - 100)^2 + 30,000
A(max) = 30,000 ft^2
when W = 100 ft
and L = 300 ft

Answer 2

You have 600 feet of fence.

Two equal parts = 300 ft each.

300 / 4 sides = 75 ft. sides.

Therefore, two areas, both 75ft. x 75ft.

Hope this helps!