How many atoms are in 27.0 g of Be metal?

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How many atoms are in 27.0 g of Be metal?

Thank you!

2007-09-16 19:34:39 · 4 answers · asked by happysqueal 2 in Science & Mathematics ➔ Chemistry

4 answers

27.0g Be x 6.022E23/9.0122gBe = 1.80E24 Be atoms

2007-09-16 21:01:39 · answer #1 · answered by prettychem 2 · 0⤊ 0⤋

Well, if you take an amount of Be defined the atomic weight of Be in grams, you get an Avogadro's number of atoms.

So, # atoms in 27 grams = (27/Atomic Weight of Be) x 6.02 x 10^23.

You can do the math. The important thing is that you understand the usefulness of Avogadro's number.

2007-09-17 02:45:50 · answer #2 · answered by Robert T 4 · 1⤊ 0⤋

Work out 27 divided by the Ar of Be, then multiply by Avogadro's number.

2007-09-17 02:45:50 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋

1.8 into 10^24

2007-09-17 02:50:18 · answer #4 · answered by smartnini 2 · 0⤊ 0⤋