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u=1
u^2+2u
which is 3 but it turned out to be wrong can you help me out?


http://i181.photobucket.com/albums/x85/ctti_3/Untitled-60.jpg

2007-09-16 19:24:59 · 2 answers · asked by sdt3 1 in Science & Mathematics Mathematics

2 answers

Evaluate the integral:

∫[(tanx + 2)/cos²x] dx

= ∫[(tanx + 2)sec²x] dx

= ∫[(tanx)(sec²x) + 2sec²x] dx

= (1/2)sec²x + 2tanx + C

I can't read the upper limit. But drop the C and evaluate the expression at the limits.

p.s. Photobucket should only be used for graphs or something that can't be typed in. We shouldn't have to go to a link to see a question that could have been easily typed in. When we have to go to a link, we can't see the question when we are answering it.

2007-09-16 21:36:08 · answer #1 · answered by Northstar 7 · 0 0

u = tan x +2
du = sec^2 x dx= 1/(cos^2 x)
u^2/2 evaluate (?,0)
I cant read the upper limit

2007-09-17 02:36:57 · answer #2 · answered by xandyone 5 · 0 0

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