Solve 1 - (x-3)/3 is less than or equal to 1/2
These interval notation problems are usually easy for. I guess I don't know what to do with the (x-3)/3.
I know the final answer is x is greater than or equal to 9/2 or [9/2 , infinity )
2007-09-16 19:19:16 · 4 answers · asked by john_ 2 in Science & Mathematics ➔ Mathematics
1 - ( x - 3 ) / 3 ≤ 1/2
6 - 2 x + 6 ≤ 3
- 2 x ≤ - 9
2 x ≥ 9
x ≥ 9 / 2
2007-09-16 20:33:42 · answer #1 · answered by Como 7 · 1⤊ 0⤋
(x-3)/3 >= 1/2
multiply by 3
(x-3) >= 3/2
add 3 to both sides of the inequality
x >= (3/2)+3
common denominator
x>= (3+6)/2
x>=9/2
2007-09-16 19:48:09 · answer #2 · answered by xandyone 5 · 0⤊ 1⤋
1 - (x-3)/3 ≤ ½
- (x-3)/3 ≤ - ½
(x-3)/3 ≥ ½
x-3 ≥ 3/2
x ≥ 9/2
-
2007-09-16 19:51:31 · answer #3 · answered by oregfiu 7 · 1⤊ 0⤋
2x/5 - a million/2 (x-3) ? 2x/3 - 3/10 (x+2) 2x/5 - x/2 + 3/2 ? 2x/3 - 3x/10 - 6/10 2x/5 - x/2 - 2x / 3 + 3x/10 ? - 6/10 - 3/2 12x/30 - 15x/30 - 20x /30 + 9x/30 ? - 6/10 - 15/10 - 14x/30 ? - 21/10 x ? (- 21/10) / (- 14/30) x ? (- 21/10) . (- 30/14) x ? 9/2 Alejandra
2016-11-15 10:32:45 · answer #4 · answered by ? 4 · 0⤊ 0⤋