Find the x and y intercepts?

Question

Find the x and y intercepts

f(x) = 9x^2 + 24x + 16

Answer 1

cuts y axis at y = 16 (y intercept)

cuts x axis at:-
9 x ² + 24 x + 16 = 0
( 3 x + 4 ) ( 3 x + 4 ) = 0
x = - 4 / 3 (x intercept)

Answer 2

At x=0 the y intercept is
9*0² + 24*0 + 16 = 16.
At y=0 the x intercepts are the roots of
0 = 9x^2 + 24x + 16 which has one repeated root at x= -4/3

Doug

Answer 3

Y intersept is math talk for set x=0
X intercept is math speak for set y=0
solve for the remaining unknown under these conditions.

@ x=0 we get:
f(x) = y = 0+0+16 = 16
@ y=0 we get:
9x^2 + 24x + 16 = 0
(3x+4)(3x+4) = 0
x = -4/3 is the x intercept.
this is a parabola that opens upward and its vertex is at -4/3.

Answer 4

f(x) = 9x^2 + 24x + 16 = (3x + 4)(3x + 4)

so f(x) = 0 at x = - 4/3

whilst when x = 0, f(x) = 16

Answer 5

To find the x-int: Make Y = 0
To find the y-int: Make X = 0

Let's find the x-int first.

0 = 9x^2 + 24x + 16

Factor it:

0 = (3x + 4 )(3x + 4 )
0 = 3x +4
-4 = 3x
-4/3 = x

Therefore, the x-int is -4/3

Let's find the y-int:

f(x) = 9(0)^2 + 24(0) + 16
f(x) = 16

Therefore, the y-int is 16

Answer 6

(3x+4)(3x +4)
x intercept= -4/3
y intercept= 16

Answer 7

x intercept, sub F(x) = 0

y-int, use F(0)