2007-09-16 17:31:31 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Take each side as the exponent of a base of ten. 10^ is the antilogarithm of log_10
10^log(x^2 + 36) = 10^log100
The 10^ and log_10 cancel out
x^2 + 36 = 100
x^2 = 64
x = ±√64 = ±8
2007-09-16 17:35:21 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Log (x^2+36)=log100
x^2+36=100
x^2=64
x=+-8
2007-09-16 17:42:15 · answer #2 · answered by Vasanth 1 · 0⤊ 0⤋
log(x^2 + 36) = log(100)
This implies that:
x^2 + 36 = 100
Subtract 36 from both sides:
x^2 = 64
Take the square root of both sides:
x = ±8
2007-09-16 17:35:55 · answer #3 · answered by whitesox09 7 · 1⤊ 0⤋
x ² + 36 = 100
x ² = 64
x = 8 , x = - 8
2007-09-17 04:59:19 · answer #4 · answered by Como 7 · 2⤊ 0⤋
plus or minus 8
2007-09-16 18:30:11 · answer #5 · answered by Katee 2 · 0⤊ 0⤋