Chemistry Help -- Theoretical Yield??

Question

In the Haber process nirtrogen reacts with hydrogen to give ammonia. What is the theoretical yield of ammonia in grams that can be prepared from 41.0 g of nitrogen and excess hydrogen?

please explain??

Answer 1

start with a balanced equation....


N2 + 3H2 ------> 2NH3

your 41.0 g nitrogen is ambigious. if it means 41 grams N, that's different than 41 g N2

let's assume it's 41 grams of nitrogen (not N2)

41.0 g N x (1 mole N / 28 g N) x ( 2 moles NH3 / 1 mole N) x ( 17 g NH3 / 1 mole NH3) = 49.8 g NH3