English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2007-09-16 17:16:54 · 2 answers · asked by cwuzzup 2 in Science & Mathematics Mathematics

d/dx x+x^1/2

2007-09-16 17:23:44 · update #1

2 answers

d/dx (x + √x)

This is your question?

Realize that √x is the same as x^(½)

And that d/dx [ f(x) + g(x) ] = d/dx f(x) + d/dx g(x)

And that d/dx x^b = b·x^(b-1)


So,
d/dx (x + √x) =
d/dx (x) + d/dx (x^(½)) =
1·x^0 + ½·x^(-½) =
1 + ½·x^(-½) =
1 + ½·√(1/x)

2007-09-16 17:21:53 · answer #1 · answered by Anonymous · 0 1

f (x) = x + x ^(1/2)
f `(x) = 1 + (1/2) x ^(-1/2)
f `(x) = 1 + 1 / ( 2x^(1/2) )

2007-09-17 18:08:29 · answer #2 · answered by Como 7 · 1 1

fedest.com, questions and answers