How to go about simplifying this exponent operation?

Question

Please show a DETAILED process of how to simplify this exponent... since i dont quite understand how to do it.

note: ^9 = 'to the power of 9'. therefore, 4^9 means 4 to the power of 9, etc.

4a^7 * b^-9 * c^-3
-------------------------- [all divided by]
3a^6 * b^-2 * c^8

Answer 1

(4*a^7 * b^-9 * c^-3) / (3*a^6 * b^-2 * c^8)
= (4*a * b^-9 * c^-3) / (3 * b^-2 * c^8)
= (4*a * b^-7 * c^-3) / (3 * c^8)
= (4*a * b^-7) / (3 * c^11)
= (4*a) / (3 * b^7 * c^11)
-

Answer 2

a million. d^3-D^-4= d^ (3-4)=d^(-a million) 2. w^21w^-12/w^9= w^(21-12)/w^9= w^9/w^9= w^(9-9)=w^0=a million 3. (3x/y)^4[x^-8/(xy)^3]^-2=[3x^4/y^4][x^-8... = [3x^4/y^4][x^sixteen/x^-6y^-6] =[3x^4/y^4][x^(sixteen+6) y^6] = 3x^4y^-4x^22y^6 = 3x^(4+22)y^(-4+6) = 3x^26y^2