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How does e^1-e^(-1) workout to be 2sinh(1)?

2007-09-16 15:58:23 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

By definition

sinh(x) = [e^x - e^(-x)]/2

Rearranging terms we have:

2sinh(x) = e^x - e^(-x)
or
e^x - e^(-x) = 2sinh(x)

Substitute in 1 for x and you have your answer.

2007-09-16 16:16:54 · answer #1 · answered by Northstar 7 · 1 0

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2016-11-14 15:52:57 · answer #2 · answered by ? 4 · 0 0

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