Find the value(s) of x for which f(x)=g(x) when f(x) = sqrt(x)-4, g(x)=2-x?

Answer 1

f(x)=g(x)
sqrt(x)-4=2-x
sqrt(x)=6-x : square both sides
x = 36 - 12x + x^2
x^2 - 13x + 36 = 0 : use the quadratic equation
x = 4 & x = 9

Answer 2

Babygirl is wrong.

f(x) = g(x)

so

sqrt(x) - 4 = 2 - x

sqrt(x) = 6 - x

Now square both sides of the equation

x = (6-x)^2

x = 36 -12x + x^2

0 = x^2 - 13x + 36

x = [13 +/- sqrt(169-4*36)]/2

= [13 +/- sqrt(25]/2

= [13 +/- 5]/2

4 or 9

Answer 3

In this scenario x can be 4 or 9
as every one knows sqrt(X*X) = (+/-) X
in case of x=4 take sqrt(4) as 2 and in case of x=9 take sqrt(9) as -3.

Answer 4

sqrt(x) can be written as x^1/2

So u take the x's to one side and the integers to the other.

Since fx=gx

x^1/2 - 4 = 2-x

x^1/2 + x = 2+4

x^3/2 = 6

Solve this using the calculator.

U get something like x = 3.3

Answer 5

x = 4 (Actual work out you may arrive at x = 9 or 4; but 9 is not acceptable; hence only one answer x = 4)