How do I simplify u^2 v^-2 / (u^4v)^-1?

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How do I simplify u^2 v^-2 / (u^4v)^-1?

please help me simplify u^2 v^-2 / (u^4v)^-1

2007-09-16 15:44:03 · 3 answers · asked by iliveinflorida 2 in Science & Mathematics ➔ Mathematics

3 answers

u²u^4v/v² = u^(4v+2)/v²

2007-09-16 15:50:02 · answer #1 · answered by chasrmck 6 · 0⤊ 0⤋

Simplify

uÂ² v^(-2) / (u^4v)^(-1)

= uÂ² v^(-2) / [(u^(-4)v^(-1)]

Now subtract powers of like terms between numerator and denominator.

= u^(2+4) / v^(-1+2)

= u^6 / v

2007-09-16 23:01:27 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋

(u^2)(v^-2)/[(u^4)( v)]^-1 =

[u^2/v^2]/1/[(u^4)( v)] =

(u^2)(u^4) (v)/v^2 =
u^6/v

2007-09-16 22:52:50 · answer #3 · answered by mohanrao d 7 · 0⤊ 0⤋