3w^2+4v-1=0?

Question

please help me to solve this problem

Answer 1

Assume:-
3 w ² + 4 w - 1 = 0
w = [ - 4 ± √ (16 + 12) ] / 6
w = [ - 4 ± √ (28) ] / 6
w = [- 4 ± 2√(7)] / 6
w = (- 2 ± √7) / 3

Answer 2

3w^2 + 4w - 1 = 0, as I think it should be?
It doesn't factorise easily, so try completing the square.
Add 1 to both sides :
3w^2 + 4w = 1
Divide both sides by 3 :
w^2 + (4/3)w = 1/3
Take half of 4/3 (= 4/6 = 2/3), then square it (= 4/9).
Add this 4/9 to both sides :
w^2 + (4/3)w + 4/9 = 1/3 + 4/9 = 7/9
The left-hand side has now been made into a square :
(w + 2/3)^2 = 7/9
Take the square root of both sides :
w + 2/3 = ± sqrt(7/9) = ± sqrt(7)/3
Subtract 2/3 from both sides :
w = -2/3 ± sqrt(7)/3

Answer 3

3v^2+4v-a million=0 v^2+4/3v-a million/3=0 v^2+4/3v=a million/3 v^2+4/3v +[4/3*2]^2= a million/3 + [4/3*2]^2 v^2 +4/3v +[4/6]^2= a million/3 + [4/6]^2 v^2+4/3v +sixteen/36 = a million/3 + sixteen/36 (a million/3 = 12/36) [v+4/6]^2 = [12+sixteen]/36 [v+4/6]^2= 28/36 ?[v+4/6]^2= ?[28/36] v+4/6 = + -[2?7]/6 (?28 =?7*?4=2?7) v = [-4+2?7]/6 and v= [-4-2?7]/6

Answer 4

you need to factor in order to solve for w. i hope you meant,

3w^2+4w-1=0. if you can't factor it, which you can't.
you need to use the quadratic formula.

use this site for help: http://purplemath.com/modules/quadform.htm

Answer 5

YOu;ve got 2 variables and 1 equation, thats impossible to answer, unless your not expecting a whole value.

w and v....wtf xD?

Answer 6

You've either mistyped this and it should be a quadratic equation or you want to transpose for v or w. You need to be more clear.

Answer 7

in terms of W or V?

Answer 8

I have no idea,