Having trouble finding an equation with specified slop and indicated point?

Question

The question is;

Find an equation of the line having the specified slope and containing the indicated point. Write your answer in slope-intercept form.

m = - 1/3; (11, -2)







So far I've gotten this;

y - (-2) = -1/3 ( x - 11)
y + 2 = -1/3x + 3 2/3
y = -1/3x + 3 2/3 - 2

But where do I go from there? and am I doing this correctly? Thanks.

Answer 1

Fine so far. Just do 3 2/3 minus 2 and see what it is, to simplify.

Answer 2

awesome work....just simplify the equation by subtracting the 2 from the 3/2/3 and then you'll have the equation in slope-intercept form

in the slope intercept form - the y must stand alone

for the point slope form, you could have y + 2 = -1/3 (x - 11)

Answer 3

You are getting there...

equation y = mx + b

y = -x/3 + b

Point (11,-2) is part of the line

-2 = -11/3 + b

-6/3 + 11/3 = b

b = 5/3

and that's how is done!

Answer 4

You did this correctly. All you have to do to finish is simplify the last step. That is, add together the numbers you have on the right side.

y=-1/3x+ (3 2/3 -2)

Answer 5

Using the standard equation of a linear function, y = mx + b, we can substitute the slope (-1/2) for m, the y-coordinate (-5) for y and the x-coordinate (11) for x. It goes like this: (-5) = (-1/2)(11) + b then we simplify -5 = -5.5 + b then we solve for b 0.5 = b With this info, we can substitute b and m back into the standard formula to get the desired equation y = -1/2x + 1/2 Tada! Hope this helps!

Answer 6

yes, it is correct
y = mx + b is the slope(m)-intercept(b) form

so you only need to do the substraction 11/3-2
Better write 11/3 instead of 3 2/3 which is cumbersome in calculations

Answer 7

y - ( - 2) = (- 1 / 3) ( x - 11 )
y + 2 = ( - 1 / 3 ) x + 11 / 3
y = ( - 1 / 3 ) x + 11 / 3 - 6 / 3
y = ( - 1 / 3 ) x + 5 / 3

Answer 8

umm.... you subtract the 2 from 3 2/3 and youre finished...

Answer 9

yes.
y=-1/3x + 5/3
3y = -x +5