What are the magnitude and direction of the hawk's velocity relative to the ground?

Question

You are in a hot-air balloon that, relative to the ground, has a velocity of 6.2 m/s in a direction due east. You see a hawk moving directly away from the balloon in a direction due north. The speed of the hawk relative to you is 1.8 m/s. What are the magnitude and direction of the hawk's velocity relative to the ground?

Answer 1

Assuming that the hawk's direction is relative to the balloon. Then we have a vector sum of (6.2,0) + (0,1.8) = (6.2,1.8). Magnitude = 6.456 m/s, angle = 16.189 deg = 16.189 deg N of E.

Answer 2

utilizing vectors, we've a real triangle with the horizontal (East) facet = 6.a million and the vertical facet (North) = a million.9. The quadratic equation (a^2 + b^2 = c^2) tells us that the hypotenuse is 6.389. that's the linked fee of the hawk relative to floor. The tangent of the attitude from East is comparable to the (opposite facet) divided by ability of the adjoining facet. So the attitude is: arctan(0.311475)