for 0<=x<360
2007-09-16 11:59:05 · 4 answers · asked by freakokalam 2 in Science & Mathematics ➔ Mathematics
Hi,
You asked twice, so I'll send it twice!!
The answers in 0 <= x <= 360 are 25° and 355°.
You can get these by entering y1 = cos(x-10) - cos(15) and looking for the equation's zeros where 0 <= x <= 360. These occur at 25° and 355°.
I hope that helps!! :-)
2007-09-19 12:19:38 · answer #1 · answered by Pi R Squared 7 · 0⤊ 0⤋
x-10 = 15 => x = 25
or
x-10 = -15+360 => x = 355
2007-09-16 12:03:35 · answer #2 · answered by sahsjing 7 · 1⤊ 0⤋
Since the arguements are the same, and we are within domain, the first angle is 25 degrees. The next angle must be in a quadrant where the Cosine is POSITIVE, which is the 4th quadrant. Since symmetry is reflected on x=0 for the cosine, the angle is 355 degrees.
2007-09-16 12:05:07 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
cos x cos 10 + sin x sin 10 = cos 15
cos x (0.9848) + sin x (0.17365 ) = 0.9659
solving . . . .
x = 0.977 radian
2007-09-16 12:12:32 · answer #4 · answered by CPUcate 6 · 0⤊ 0⤋