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Ok the problem is:
(3x^3-2ax^2+bx+1) - (cx^3+5x^2-7x+9) = -x^3+x^2-2x+4d
I am so confused, especially on how to add and subtract the exponents. Can you explain this to me?

2007-09-16 11:03:35 · 6 answers · asked by DD 2 in Science & Mathematics Mathematics

I.E. I'm trying to find the values for a b c and d.

2007-09-16 13:38:56 · update #1

6 answers

so i am assuming you are trying to find a b and c?

so this is in order so that will be nice.

3x^3-cx^3=-1x^3. you are not subtracting exponents. find the number before the x's. so whats 3-c=-1? c is 4. and do this for the next ones. just write down the smaller equations like i did.

you make those by grouping similar items together. so the x^3 can be added and stutracted and likewise the ^2 and ^1 which is just x.

i will not do the rest for you. just sit and think for a moment and then you will get it.

2007-09-16 11:09:06 · answer #1 · answered by gonavy271 2 · 0 0

(3x^3-2ax^2+bx+1) - (cx^3+5x^2-7x+9) = -x^3+x^2-2x+4d

What are you trying to do?

(3x^3-2ax^2+bx+1) - (cx^3+5x^2-7x+9) = -x^3+x^2-2x+4d
(3x^3-2ax^2+bx+1) -cx^3 - 5x^2 + 7x -9 = -x^3+x^2-2x+4d
(3-c)x^3 + (-2a - 5)x^2 + (7+b)x -8 = -x^3 + x^2 - 2x + 4d


you're not subtacting any exponents when you're adding. You only add the exponents when you're multiplying/dividing. i.e. (x^5)(x^8) = x^(8+5)= x^13 or (x^5) / (x^8) = 1/x^3

if you're adding. i.e. (3x^2 + x + 5) + (x^3 + x^2) then collect the like terms. x^3 + 4x^2 + x + 5

I'm still confused of what you're trying to ask.

2007-09-16 18:12:12 · answer #2 · answered by Memories 4 · 0 1

only terms with similar variables and exponents can be added or subtracted.
if the exponents are different then factor, if the bases are the same.

(3x^3-2ax^2+bx+1) - (cx^3+5x^2-7x+9) = -x^3+x^2-2x+4d
Remove the ()
3x^3-2ax^2+bx+1-cx^3-5x^2+7x-9=-x^3+x^2-2x+4d
move everything to the left
3x^3-2ax^2+bx+1-cx^3-5x^2+7x-9+x^3-x^2+2x-4d=0
4x^3-cx^3-6x^2-2ax^2-5x+bx+4d-8=0
x^3(4-c)-2x^2(3-a)-x(5-b)+4(d-2)=0
x^2(x(4-c)-2(3-a))-x(5-b)+4(d-2)=0

2007-09-16 18:25:00 · answer #3 · answered by 037 G 6 · 0 0

You have to find a,b,c & d such that
(3x^3-2ax^2+bx+1)-(cx^3+5x^2-7x+9)=-x^3+x^2-2x+4d
compare co-eff
Now 3x^3-cx^3=-x^3, so c=4
similarly a=-3,b=-9 & d=-2 ans

2007-09-16 18:24:02 · answer #4 · answered by MAHAANIM07 4 · 0 0

try inputting a value for x. I reccommend 4. It always works with me! And i guess it has something to do with quadratic equations. i think you should bring -x^3+x^2-2x to the other side by dividing, and leave 4d. then input x to find d. i hope it works.

2007-09-16 18:14:25 · answer #5 · answered by Harris 6 · 0 1

What grade are you in?!?

2007-09-16 18:07:30 · answer #6 · answered by Anonymous · 0 2

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