The length of a rectangle is 5 meters longer than the width?

Question

The length of a rectangle is 5 meters longer than the width. Find the length and width if the perimeter is 54 meters.

Answer 1

2 x (length) + 2 x (width) = perimeter
2 ( x) + 2 (x + 5) = 54
2x + 2x + 10 = 54
4x + 10 = 54
4x = 44
x = 44/4
x = 11 (width)
y = 11 + 5 = 16 (length)

Answer 2

I wont do it for you because that way you wont learn. Here is an example.

A rectangle is 3 meters longer than its width. Width is 60m

longside + small side + long side + small side = permimeter

(x+3) + x + (x+3) + x = 60m

so:

4x + 6 = 60
4x = 60 - 6 = 54
x = 54 / 4 = 13.5

X = 13.5 or width

X+3 or 13.5 + 3 = 16.5 or length.

Answer 3

let perimeter = 54
width = w
length = w + 5
then your formula for the perimeter of rectangle is:
P = (2*l) + (2*w) so
54=2(w+5)+2*w
54=2w+10+2w
44=4w
w=11 & w+5=16
so to check: 11+11+16+16=54
hope this helps!

Answer 4

perimeter = 54 = 2l + 2w = 2 (w + 5) + 2w = 4w + 10

4w = 44
w = 11
l = 16

area = l*w = 11*16 = 176 sq m

Answer 5

w=w
L = w + 5
P = 54

Perimeter = 2L + 2w

2(w + 5) + 2w = 54

2w + 10 + 2w = 54

4w + 10 = 54

4w = 44

w = 11



2(11) + 2L = 54

22 + 2L = 54

L = 16