Maths Help!?

Question

Im so stuck! I can't simplify these quadratic expressions: -

1) x^2 + x - 6 / x^2 - x - 2

2) x^2 + x - 2 / x^2 + 4x + 3

How do i do it!! Help!!

Answer 1

1) (x^2+x-6)/(x^2-x-2)

= ((x-2)(x+3))/((x-2)(x+1))

cancel the (x-2)

= (x+3)/(x+1)

2) (x^2+x-2)/(x^2+4x+3)

= ((x+2)(x-1))/((x+3)(x+1)) which does not simplify any more

Answer 2

Question 1

x^2+x-6 = (x-2)(x+3)

x^2-x-2 = ((x-2)(x+1)

(x-2)(x+3)/(x-2)(x+1) = (x+3)/(x+1) Ans

Question 2

x^2 + x -2 = (x+2)(x-1)

x^2+4x +3 = (x+3)(x+1)

(x+2)(x-1)/(x+3)(x+1) Ans.

It cannot be simplified any further unless you do the long division

Answer 3

1) (x^2 + x - 6) /( x^2 - x - 2)

Hopefully, the above is what you meant

Factor the trinomials to see if any cancellation can take place

[(x + 3)(x - 2)]/[(x - 2)(x + 1)]

(x + 3)/(x + 1)


2) (x^2 + x - 2) /( x^2 + 4x + 3)

[(x + 2)(x - 1)]/[(x + 3)(x + 1)]

Nothing to cancel here

Answer 4

You're not given any values so they are not equations.
1) x^2 + x - 6 / x^2 - x - 2
Factor both into binomials:
(x + 3)(x - 2)/(x + 1)(x - 2)
Cancel out the common factor:
(x + 3)/(x + 1)

2) x^2 + x - 2 / x^2 + 4x + 3
Factor both into binomials:
(x + 2)(x - 1)/(x + 3)(x + 1)
No common factor:

Answer 5

I'm not very good at maths but this site looks very good.

Click on link.

Hope it helps. It's best to do it yourself then you will understand it a bit better.

Answer 6

Combine the x's on both sides giving you

1) 2x^2-6 / -x^-2

Actually I don't really know, good luck!

Answer 7

1. 2x(x-6)/2x(x-2)

2. 2x(x-2)/2x(4+3)

Answer 8

What the hell is "^"?