Hopefully get an answer?

Question

Thanks to a Yahoo Physcis expert they gave me the following:

´h=-16*t^2 +70 feet
v=-32 *t feet/s
h=0 t^2 = 70/16 so t =sqrt(70/16)=2.09 s

Can I get the answer too for each calculation? Just want to double check what I am doing is right

Answer 1

Corrected
This cannot be solved the way it is presented. You have two equations and three unknowns, h, t and also v which also depends of t. The last line of calculation is meaningless.
Now if v=32 ft/s instead of "32 t ft/sec" it can be solved. Here it is being indicated in the first equation that the acceleration of that gravity is "32". (d=1/2gt^2)
If the stated velocity is 32, the time has been 1 sec.
v=at; 32= 32t so t =32/32 = 1sec
so h=-16(1)^2 +70; h= -16x1+70 = -16+ 70 = 54 ft

Answer 2

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