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How do you solve i^-35?

Can you please explain?

2007-09-16 07:20:57 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

1 answers

Observe
i^1=i
i^2=-1
i^3=-i
i^4=-i^2=1 ond so on.
If the exponent is a multiple of 4 the power is 1
so
i^-35 = 1/ i^35 = i/i^36 =i

2007-09-16 07:30:35 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

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