I you dropped a ball from a 70 feet, how do I calculate the velocity of the ball? How about a calculation for how long it is in the air before it hits ground? And lastly determining a function for the height of the ball t seconds after it's released? Sorry but thanks, this is a tough one........
2007-09-16 07:11:01 · 3 answers · asked by Cutekow 2 in Science & Mathematics ➔ Physics
First you determine the time of the fall from 60 feet. Divide 60 by 16 and find the square root of this number, it will be 2.09 seconds, the final velocity of the ball will be 2.09 X 32=66.93 feet per second. You can do the rest of the math.
2007-09-20 06:39:56 · answer #1 · answered by johnandeileen2000 7 · 0⤊ 0⤋
´h=-16*t^2 +70 feet
v=-32 *t feet/s
h=0 t^2 = 70/16 so t =sqrt(70/16)=2.09 s
2007-09-16 07:21:39 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
The equation for velocity is displacement divided by the time.
2007-09-16 07:18:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋