Calculus help ?? complete the square : 2x^2-x+1?

2 ⤊

Calculus help ?? complete the square : 2x^2-x+1?

show your solution please, thank you

2007-09-16 06:00:54 · 3 answers · asked by Im here 2 in Science & Mathematics ➔ Mathematics

3 answers

2x^2-x+1
= 2(x^2 - x/2 + 1/16) - 1/8 + 1
= 2(x -1/4)^2 + 7/8

2007-09-16 06:09:00 · answer #1 · answered by sahsjing 7 · 1⤊ 0⤋

= 2 [ x Â² - (1/2) x + (1/2) ]
= 2 [ ( x Â² - (1/2) x + 1/16 ) - 1/16 + 1/2 ]
= 2 [ (x - 1/4) Â² + 7/16 ]
= 2 (x - 1/4) Â² + 7/8

2007-09-16 13:45:29 · answer #2 · answered by Como 7 · 1⤊ 0⤋

Your square will be 2x^2-x+c, c is unknown. For this to be a square 2*(sqrt2)*sqrt(c) = -1 or, squaring both sides, 4c=1 and c=1/4. So, we have 2x^2-x+(1/4) +(3/4).

2007-09-16 13:11:12 · answer #3 · answered by cattbarf 7 · 0⤊ 1⤋