can someone answer this chemistry question?

Question

a post-operative patient is to receive 300 mg of intravenous (IV) antibiotic every 4.00 hours. A 1.00 liter bag of IV solution contains 500mg of antibiotic. what drop rate (in drops per second) of IV solution is required for the patient to receive the correct dosage of antibiotic? (20 drops = 1ml)

Answer 1

20 drops = 1mL

If 500 mg = 1000 ml, then 300 mg = 1000*300 / 500 = 600ml

1 ml = 20 drops
600 ml = 20 * 600 = 12000 drops

No of drops per hour needed = 12000 / 4 = 3000 drops per hour.

Answer 2

The IV bag holds 20*1000 drops = to 500mg
therefore 300mg will be 3/5 of the total =.12000 drops
4hrs=14400seconds
dosage=1.2 drops /second

Answer 3

Lets start with the bag.
Each mL contains 0.5 mg antibiotic. (500mg/L)
So the person requires 600 mL in 4 hours. 300mg/[0.5 mg/mL]
This is equivalent to 12000 drops. (600x20)
Four hours = 14,400 seconds. 3600x4
So patient gets 12000/14400 or about 0.84 drop/second.

Answer 4

300 mg/hr
x
1 L / 500 mg
x
1000 mL / L
x
20 drops / mL
x
hr / 3600 s

= 1 1/3 drops/s