Suppose a parallelogram has sides of length 4 and 8 and the height to the shorter base is 6. What is the height to the longer base?
I got an answer to this problem but I don't think it is right, the answer I got was the square root of 52.
Does anyone have a better answer?
THANKS!
2007-09-16 05:07:41 · 4 answers · asked by Abby S. 2 in Science & Mathematics ➔ Mathematics
Thanks everyone for your answers! I will be picking a best answer in a couple of minutes.
2007-09-16 05:31:03 · update #1
The opposite angles of a parallelogram are the same.
So if you draw it...from the short bases... (which is the longest height) and that angle is A, then the
Sin A=Opposite/Hypotenuse
Sin A = 6/8
In your other Triangle with your unknown height it would be:
Sin A=x/4
So 6/8=x/4
X=3
2007-09-16 05:26:45 · answer #1 · answered by Patty C 3 · 1⤊ 0⤋
4*6 = h*8, the area of the parallelogram
Solve for h,
h = 3, the height to the longer base.
2007-09-16 05:12:04 · answer #2 · answered by sahsjing 7 · 1⤊ 0⤋
I don't recall the exact method, but a quick sketch shows that it has to be less than 4 (less than the square root of 16) because it it were a rectangle the height would be 4 and tilting it lowers the height.
2007-09-16 05:15:04 · answer #3 · answered by Mike1942f 7 · 1⤊ 0⤋
Area of ||-orgram = bh = 6*4=24
So 8x=24 --> x= 3 = height to longer side
A = b1*h1 = b2*h2
2007-09-16 05:21:43 · answer #4 · answered by ironduke8159 7 · 1⤊ 0⤋