One more sequence question...?

Question

Find t5 given that:

t1 = 4, tn+1 = 6 + tn

full solution please.

Answer 1

t[1] = 4, t[n+1] = 6 + t[n] (I'm writing subscripts in square brackets)
Just go step by step:

t[2] = 6 + t[1] = 6 + 4 = 10
t[3] = 6 + t[2] = 6 + 10 = 16
and now you see how to continue:
t[4] = 22, t[5] = 28.

Ideally you work out the general expression for t[n], namely
t[n] = 4 + 6(n-1), and just plug in n = 5. But that might be a different question for your course.

Answer 2

t1=4
t2= 6+4= 10
t3 = 6+10 = 16
t4 = 6+16 = 22
t5 =6+22 = 28

Answer 3

I think you mean....

The first term is 4.

The (n +1)th term is 6 more than the nth term.

This is just another way to express an arithmetic sequence. This one goes 4 10 16 22 28. You want the fifth term.