This is a question an an ACT practice test i'm taking now. My hint is think of the two points as the hypotenuse of a right triangle, but how does that help? I mean if you don't know the value of the "legs" of the triangle its no good....right??? plz help.
2007-09-16 04:30:26 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sqrt( (x1-x0)^2 + (y1-y0)^2 + (z1-z0)^2) for 3 dimensions.
sqrt( (x1-x0)^2 + (y1-y0)^2) for 2 dimensions.
2007-09-16 04:33:35 · answer #1 · answered by Elana 7 · 0⤊ 0⤋
Given two points, P₁=(x₁, y₁) and P₂=(x₂, y₂)
Applying the Pythagorean Theorem,
c² = a² + b²
The distance between P₁ and P₂ (d) is
d = â[(x₂ - x₁)² + (y₂ - y₁)²]
2007-09-16 04:45:09 · answer #2 · answered by gugliamo00 7 · 0⤊ 0⤋
Point 1 has coordinates (x, y)
Point 2 has cprdinates (u, v)
The distance between them is ((x-u)^2 + (y-v)^2)^0.5
2007-09-16 04:36:52 · answer #3 · answered by Scott H 3 · 0⤊ 0⤋
Given 2 points (x1,y1) and (x2,y2) you --do-- know the lengths of the legs (if you'd been paying attention in class). They're
x=x2-x1 and
y=y2-y1
HTH
Doug
2007-09-16 04:37:56 · answer #4 · answered by doug_donaghue 7 · 0⤊ 0⤋