Precalc help .. thanks.
2007-09-16 04:21:57 · 5 answers · asked by ilovesoccer 1 in Science & Mathematics ➔ Mathematics
as u cannot do the square root of negative number, the domain is any values larger than 4 or smaller than -4 inclusive.
range is all values larger than 0 inclusive.
the question is actually the root(x^2 - 16) a couple of people have read it incorrectly as being x^2 - 16 which is a parabola..
2007-09-16 04:26:01 · answer #1 · answered by Anonymous · 0⤊ 0⤋
y = sqrt(x^2-16)
Domain is all the real numbers >= 4 and ,<= -4
Range is [0, infinity).
2007-09-16 04:28:30 · answer #2 · answered by ironduke8159 7 · 1⤊ 0⤋
Very weird question, but so far I got
f(x) = x - 4
Maybe that helps some because you can bring the square root of the 2 things in there out, to get x and -4. Good luck
2007-09-16 04:26:36 · answer #3 · answered by Mythical Tales 6 · 0⤊ 1⤋
I'm guessing that your restricted to real numbers, so the domain is all {x | x≥4} and the range is all of the reals.
Doug
2007-09-16 04:28:12 · answer #4 · answered by doug_donaghue 7 · 0⤊ 1⤋
area and selection of f(x)=sq. root of (sixteen-x^2) area A = {x|x?R and -4? x ?4} selection B = {x|x?R and 0? x ?4} pondering purely beneficial sq. root. the two posotive and unfavorable can not be taken through fact then it can not be a function
2016-10-09 06:57:06 · answer #5 · answered by lindenberg 4 · 0⤊ 0⤋