Solve the system by addition.
Can someone please help me with this? Please, the points are yours.:)
2007-09-16 03:46:33 · 4 answers · asked by momscharm1964 1 in Science & Mathematics ➔ Mathematics
2(3x-2y= -17) 6x-4y=-34 7x=-21
+ x+4y=13 + x+4y=13 ** x=-3***
-3+4y=13 4y=14 ***y=4**
2007-09-16 03:58:32 · answer #1 · answered by foofy 4 · 0⤊ 0⤋
foofy is right, she got the answer. x=-3 and y=4. Not so sure how though....
3x - 2y = -17
then multiply the x + 4y = 13 by -3 to cancel out the x's
so
3x - 2y = -17
-3x - 12y = -39
and then add the like variables to get
0x - 14y = -56
Then divide by -14
-56/-14 equals
y=4
So then
3x -2y = -17
3x - 2(4) = -17
3x - 8 = -17
add the 8 to the other side
3x = -9
divide by 3
x=-3
2007-09-16 11:02:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2*(3x-2y=-17) => 6x-4y=-34 so
6x-4y=-34
x+4y=13
7x = -21
x = -2 Now plug -2 in for x in either of the equations and solve for y
Doug
2007-09-16 11:01:02 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
Do you need to solve for one X and one Y, or two Xs and two Ys?
2007-09-16 10:54:52 · answer #4 · answered by Mythical Tales 6 · 0⤊ 0⤋