cud any one help me i have to find the 1st 4 terms a 3n+1 b 4n - 2 c 2n +7 d 6n -5 e 2n - 9?

Question

a 3n+1 b 4n - 2 c 2n +7 d 6n -5 e 2n - 9

Answer 1

a
T1= 3n+1= 4..........n=1
T2 = 7
T3 = 10
T4 = 13

b
T1= 4n - 2 = 2........n=1
T2 = 6 , 10, 14


c
T1 = 2n +7 = 9....n=1
T2 = 11,13,15

d
T1 = 6n -5 = 1........n=1
T2 = 7,13,19

e
T1 = 2n - 9 = -7
T2 = -5,-3,-1

QED

Answer 2

Here is a complete answer:

a) 3n+1 = 4, 7, 10, 13….

b) 4n-2 = 2, 6, 10, 14 …

c) 2n+7 = 9 , 11, 13, 15 ….

d) 6n-5 = 1, 7, 13, 19 ….

e) 2n-9 = -7, -5, -3, -1 …..

Answer 3

Is this a five-part question, where the first part is to give the first four terms of f(n) = 3n + 1, etc.? If so, just put in 1, 2, 3, 4 for n: 3(1) + 1 = 4, 3(2) + 1 = 7, 3(3) + 1 = 10, and 3(4) + 1 = 13. See?

Answer 4

Oh Oh i like algebra a million+4+7+(3n-2)=n(3n-a million)2 12(3n-2)=n(3n-a million)2 36n-24=n(3n-a million)2 24=36n(3n-a million)2 24=(108n-a million)2 23=(108n)2 23=fifty 4 hmmmm does not look good i think of i'm going to easily save on with makeup than

Answer 5

(to find the 1st four terms, we must have n=1, 2, 3, 4)
Just substitute n
a. 3n+1
Ans. 4, 7, 10, 13

b. 4n-2
Ans. 2, 6, 10, 14

c. 2n+7
Ans. 9, 11, 13, 15

d. 6n-5
Ans. 1, 7, 13, 19

e. 2n-9
Ans. -7, -5, -3, -1

Answer 6

dude u will have to specify thats these terms are in AP GP HP or in what format