A ball is thrown vertically at 20ms^-1?

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A ball is thrown vertically at 20ms^-1?

A ball is thrown vertically at 20ms^-1 from the surface of the Earth. With what speed would it have to be thrown on Jupiter, where g is = 22.5ms^-2, in order to reach the same height?

2007-09-16 00:29:48 · 3 answers · asked by ur having a right laugh innit 2 in Science & Mathematics ➔ Physics

3 answers

v^2=2ah; v=sqrt(2ah)
Thus v(j) = v(e)*sqrt(a(j)/a(e)) = 20*sqrt(22.5/9.81) = 30.289 m/s.
If you're using 10 m/s^2 as a(e), then it's 20*sqrt(2.25) which is exactly 30.

2007-09-16 02:08:11 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋

The ball goes up to 20m height on earth (V^2=2a*h).
so according to the above formula the ball must be thrown vertically at 30m/s

2007-09-16 01:47:30 · answer #2 · answered by Ali T 2 · 0⤊ 0⤋

jupiter or moon

2007-09-16 00:34:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋