Im Bad at maths can someone please tell me the answers to these questions?

Question

5. Find the value of the letter (s) in each of these questions:
a) 96 = 2^m x 3
b)378= 2 x 3^n x 7
c) 8500 = 2^m x 5^n x P
d) 3591 = 3^m x 7 x Q


Thanx =]

Answer 1

problems (c) and (d) are unsolvable. You need one equation per variable in order to get a numeric answer for each of the variables. This can be a system of equations, but not only one equation to solve for 3 variables as in (c) or 2 variables as in (d)

As for (a),

96 / 3 = 2^m
32 = 2^m

Think of what power is needed on 2 to get 32.

(b)
378 = 14 * 3^n
378 / 14 = 3^n
27 = 3^n

Think of what power is needed on 3 to get 27.

Answer 2

These are actually not as hard as they initially look. Notice that they're asking you to find products of prime numbers. Thus, you can use division by primes. This is done by dividing the number as many times by two as possible, then moving to 3, 5, 7, etc.

So,
a. 96/2 = 48/2 = 24/2 = 12/2 = 6/2 = 3. There are 5 twos so m = 5.

b. 378/2 = 189/3 = 63/3 = 21/3 = 7.
n = 3.

c. 8500/2 = 4250/2 = 2125/5 = 425/5 = 85/5 = 17.
m = 2, n = 3, and P = 17.

d. 3591/3 = 1197/3 = 399/3 = 133/7 = 19.
m = 3, Q = 19.

Answer 3

96 = 2^m (3)
2^m = 32 = 2^5
m = 5

b) . . . 378 = 2 ( 2^n )(7)
2^n = 27
n log 2 = log 27
n = log 27 / log = 24.755

c) . . . 8500 = 2^m x 5^n x p
what is the variable?

Answer 4

a) 96/3=32
so 2^m=32
32/2=16
16/2=8
8=2^3 (if do not this u are deep trouble)
so m=5 (3+1+1) ((1 for each division of 2))

answer 5
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b &c)please me resubmit using brackets to show what is to the power n because nothing is dropping clear
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d)3591==3^m*7*Q
are we using answer a)
if so
3^5=243
243*7=1701
3591/1701=2 1/9 or (2.111111111111111111111111111111111111111111111)

Answer 5

It is best if you ask someone how to do it, so you understand in the future.

Answer 6

a)
2^m=32=2^5

m=5

b)
3^n=27=3^3

n=3

c)8500=2^5x5^3xP=32x125xP

P=2.125

d)3591=3^5x7xQ=243x7xQ

Q=2.111111111111111111111111111111