'cos if I could do trig I wouldn't be asking on here.
2007-09-15 22:59:41 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
CPUcate didn't read the question.
It is the SIDES whose values are given; it is the angles that are required.
Thank you.
2007-09-15 23:14:37 · update #1
203 unhelpful. This is not homework, this a carpentry project at home and using Yahoo is the way I work it out; so what's wrong with just posting the solution?
2007-09-15 23:16:26 · update #2
Thank you helpful people.
2007-09-15 23:38:01 · update #3
You will need to use the Law of Cosines:
Assuming you can plug numbers into an equation and chug out the number, you should be fine. I'll even go as far as to set up the equations for you, but you can pick up the calculator :)
A = 51
B = 51
C = 60
a = angle measure opposite the sides of length 51
c = angle measure opposite the side of length 60
A^2 = B^2 + C^2 - 2B*C*cos (a)
C^2 = A^2 + B^2 - 2A*B*cos(c)
a = 54 degrees, approximately.
c = 72 degrees, approximately.
2007-09-15 23:18:20 · answer #1 · answered by lhvinny 7 · 1⤊ 0⤋
Draw a perpendicular from the vertex to the base.
Your base now is divided into two equal lines, each of 30.
The two side angles are equal with a value of :
angle = inverse of cos (30/51) = 53.968 degrees (almost 54 degrees)
The vertex angle (the top Angle) = 180 -( 2x53.968) = 72.064 degrees (almost 72 degrees)
So, your angles will be 72,54,54 degrees
2007-09-16 06:39:39 · answer #2 · answered by best-doctor 2 · 1⤊ 0⤋
given the sides, you just need to use cosine law...
angle A = arccos(B^2 + C^2 - A^2/ -2BC)
below are the sides and the angles
opposite them...
side a = 51
angle A = 53.96812 degrees
side b = 51
angle B = 53.96812 degrees
side c = 60
angle C = 72.06376 degrees
hope this helps...
cheers!
2007-09-16 06:22:25 · answer #3 · answered by quigonjan 3 · 0⤊ 0⤋
If you can't do the trig, get a compass, ruler and protractor. Use the compass and ruler to draw the triangle and use the protractor to measure the angles.
2007-09-16 06:39:55 · answer #4 · answered by Pete WG 4 · 0⤊ 0⤋
given the sides, you just need to use cosine law
2007-09-16 06:51:57 · answer #5 · answered by ? 3 · 0⤊ 0⤋
if the interior angles of a triangle is not EXACTLY 180 deg
then it is not a triangle
2007-09-16 06:09:32 · answer #6 · answered by CPUcate 6 · 0⤊ 2⤋
There's no yahoo answers come exam time.
It will be in your best interest to work towards understanding it for yourself.
2007-09-16 06:13:41 · answer #7 · answered by 203 7 · 1⤊ 2⤋