Graph the solution set of x<-7 Give details please?

Answer 1

There are two possible ways to do this. The set is ALL numbers less than -7. On a simple number line, make a number line that shows the following:

<----|-------|--------|-------|-->
-10.....-9........-8......-7

Put an open dot (or circle) on the -7 and a solid line all the way to the left, including the arrow.

<==|===|===|===o-->
-10.......-9......-8...-7

BUT....
If you graph it on a coordinate plane, draw a vertical line that crosses the x-axis at -7. It should be dotted since you are NOT including -7 (everything less than that....a solid line means you are including it in the set). Then shade everything to the left.

Answer 2

The guy above is close. You want to draw a vertical dotted line going through -7. Now where to shade? Where will the numbers be that are less than -7? Check any number to the right: Is 10 less than -7? If you said 10 is less than -7 you would shade to the right but if you said 10 is not less than -7 you would shade to the left of your graph.

Do not listen to the one whose source say 11 years teaching math. Your problem is an inequality and is not graphed on a number line!

Answer 3

Draw a dashed vertical line through the point(-7,0)
Shade everything to the left of this line. All points in the shaded area satisfy the equation. Points cannot be on the dashed line.

Answer 4

draw a vertical line at x = -7
then everything to the left of the line and excluding the points on the line is the solution set

Answer 5

draw the line x = -7

then work out which side the point of origin (0,0) lies on.

as this point would be greater than -7 then you know you need whatever is LESS than -7 and so the point of origin is on the side of the line you dont want so you can shade that area to get your answer