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A glacier advances at 7x10^-6 cm/s. How far will it move in 3.8 years? Answer in units of cm.

2007-09-15 13:44:09 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

this is a simple speed over time problem.... or velocity. same as if I were to say how far will a car go in 1 hour if traveling 60mph.

so start with converting 3.8 years to seconds. 3.8 years x 365 days/year x 24 hours/day x 60 min/hour x 60 s/min x 7 x10^-6 cm/s --> cancel all units and multiple you get 838.858 cm

2007-09-15 13:56:08 · answer #1 · answered by Chip 2 · 0 0

First you need to find out how many seconds are in a year, and then multiply what you find by 3.8 years.

The number of seconds in a year are 60 seconds x 60 minutes x 24 hours x 365 days = 31,536,000.

Now, multiply the number of seconds in a year by 3.8 years:
31,536,000 x 3.8 = 119,836,800, or 1,198,368 x 10^2.

Now that you know how many seconds are in 3.8 years, multiply that number by 7 x 10^-6:
(1,198,368 x 10^2) x (7 x 10^-6)

Next, multiply 1198368 and 7 together and multiply it by 10 ^ -4 (add the exponents together):
8,388,576 x 10^-4

The answer to your question is that the glacier will advance 8,388,576 x 10^-4 cm/s in 3.8 years.

2007-09-15 14:28:23 · answer #2 · answered by peaceablefruit206 7 · 0 0

The velocity of the gacier = 7 x 10^-6 cms/sec
Duration ...= 3.8 years
...= 3.8 x 365 x 24 x 3600 sec= 119836800
Dist. covered = 119836800 x 7 x 10^-6
........................= 838857600 x 10^-6
........................= 838.9 cms or 8.389 metres
.....................===============

2007-09-15 14:06:10 · answer #3 · answered by Joymash 6 · 0 0

7x10^-6 cm/s * 3.8 yr * 365 da/ yr * 24 hr/da * 3600 sec/hr = 838.86 cm
.

2007-09-15 13:58:00 · answer #4 · answered by Robert L 7 · 0 0

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