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The math problem is x/5 =2x-6

I have the answer but I need to show my work and I can't figure it out. Please help and send me your steps!

THANK YOU!!!!

2007-09-15 13:24:42 · 5 answers · asked by Sweet Susie 4 in Education & Reference Homework Help

5 answers

x/5 = 2x-6
x = 5(2x-6)
x = 10 x - 30
30 = 9x
x = 30/9
x = 10/3

done

2007-09-15 14:59:40 · answer #1 · answered by Anonymous · 0 0

First multiply both sides by 5 to remove the left denom.

5(x/5) = 5(2x-6)
so
x=10x-30

subtract 10x from both sides to move all x's on left side
x = 10x-30
-10x -10x

so
-9x = -30

then divide by -9 on both sides to isolate x and remove negative

-9x = -30
___ ___
-9 -9

and
x = 10/3 or 3 and 1/3
but math teachers like improper fractions, not mixed numbers

2007-09-15 13:36:22 · answer #2 · answered by glazeddonut27 3 · 0 0

x/5=2x-6
move 5 to the right hand side(rhs), because 5 is divided on the lhs, it will be multiply at the rhs
so,
x= 5*(2x-6)
x= 10x-30
move 30 to the lhs and x to the rhs,
30=10x-x
rearrange the equation
10x-x=30
9x=30
x=30/9
simplify the answer.

2007-09-15 13:34:12 · answer #3 · answered by curiouscrew 2 · 0 0

x/5=2x-6

Multiply both sides by 5

x=5(2x-6)
x=10x-30
x-10x=10x-10x-30
-9x=-30
-9x/-9=-30/-9
x=3 3/9=3 1/3

2007-09-15 13:39:06 · answer #4 · answered by Dave aka Spider Monkey 7 · 0 0

first, get X on one side by subtracting 2x from both
-2x + x / 5 = -6

divide both sides by 5
-2x + x = -6 / 5

simplify by combining like terms
-x = -1.2

divide both sides by -1 to change sign
x=1.2

2007-09-15 13:34:37 · answer #5 · answered by BioHazard 5 · 0 1

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