7x + 15y = 32
-7( x - 3y = 20)
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7x + 15y = 32
-7x + 21y = -140
Add them together vertically
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0x + 36y = -108
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y = -3
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Now place -3 in place of "y" in one of your equasions
x - 3(-3) = 20
x + 9 = 20
x = 11
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Answer:
x = 11
y = -3
2007-09-15 11:31:30
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answer #1
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answered by Kyle R 2
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Multiply 2nd equation by 7 and subtract from the 1st.
You eliminate x and you get y(15+21) = (32-140)
or 36y = -108 or y =-108/36 = -27/9 = -3
Substitute in equation #2 and you get
x -(3x-3) = 20 or x+9 = 20 or x=11.
2007-09-15 11:36:35
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answer #2
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answered by stvenryn 4
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7x+15y=32
x-3y=20
multiply the second guy by five and add to the first
12x = 132
x = 11
(11)-3y = 20
-3y = 9
y = -3
2007-09-15 11:28:26
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answer #3
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answered by PMP 5
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7x+15y=32----------------(1)
& x-3y=20------------------(2)
multiplying (2) by 5 ,we have
5x-15y=100----------------(3)
adding (1) & (3)we get
12x=132
or x=11,putting this value in (2)we get
11-3y=20 or -3y=20-11=9 or y=-3 ans
2007-09-15 11:33:41
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answer #4
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answered by MAHAANIM07 4
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x = 20 + 3y . . . . substitute to the other equation
7(20 + 3y ) + 25 y = 32
140 + 21 y + 25 y = 32
46 y = - 108
y = - 54 / 23
2007-09-15 11:41:15
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answer #5
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answered by CPUcate 6
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multiply the second by 5
5x - 15y = 100
add
12x = 132
x = 11; y = -3
2007-09-15 11:30:48
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answer #6
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answered by Beardo 7
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are you solving for x or y?
2007-09-15 11:28:27
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answer #7
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answered by Tim S 2
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