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it says solve by elimination..

2007-09-15 11:22:55 · 7 answers · asked by Sam 1 in Science & Mathematics Mathematics

7 answers

7x + 15y = 32
-7( x - 3y = 20)
___________________

7x + 15y = 32
-7x + 21y = -140

Add them together vertically
___________________

0x + 36y = -108

___________________

y = -3
___________________

Now place -3 in place of "y" in one of your equasions

x - 3(-3) = 20

x + 9 = 20

x = 11
_______________

Answer:
x = 11
y = -3

2007-09-15 11:31:30 · answer #1 · answered by Kyle R 2 · 1 0

Multiply 2nd equation by 7 and subtract from the 1st.

You eliminate x and you get y(15+21) = (32-140)
or 36y = -108 or y =-108/36 = -27/9 = -3
Substitute in equation #2 and you get

x -(3x-3) = 20 or x+9 = 20 or x=11.

2007-09-15 11:36:35 · answer #2 · answered by stvenryn 4 · 0 0

7x+15y=32
x-3y=20

multiply the second guy by five and add to the first

12x = 132
x = 11
(11)-3y = 20
-3y = 9
y = -3

2007-09-15 11:28:26 · answer #3 · answered by PMP 5 · 0 0

7x+15y=32----------------(1)
& x-3y=20------------------(2)
multiplying (2) by 5 ,we have
5x-15y=100----------------(3)
adding (1) & (3)we get
12x=132
or x=11,putting this value in (2)we get
11-3y=20 or -3y=20-11=9 or y=-3 ans

2007-09-15 11:33:41 · answer #4 · answered by MAHAANIM07 4 · 0 0

x = 20 + 3y . . . . substitute to the other equation
7(20 + 3y ) + 25 y = 32
140 + 21 y + 25 y = 32
46 y = - 108
y = - 54 / 23

2007-09-15 11:41:15 · answer #5 · answered by CPUcate 6 · 0 0

multiply the second by 5

5x - 15y = 100

add

12x = 132

x = 11; y = -3

2007-09-15 11:30:48 · answer #6 · answered by Beardo 7 · 0 0

are you solving for x or y?

2007-09-15 11:28:27 · answer #7 · answered by Tim S 2 · 0 0

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