(a) 2/5,3/5
(b) 5/8,7/8
How do you solve these problems?
2007-09-15 10:39:53 · 5 answers · asked by Kris 1 in Science & Mathematics ➔ Mathematics
Change the fifths to tenths. 4/10 and 6/10. Remember to double the tops and the bottoms. Pick 5/10 because it is in the middle. You can also use 1/2.
For the eighths, notice that it is 5 and 7. In between those two is is 6/8. To simplify, divided by a common factor (2). 3/4 will also work.
2007-09-15 10:48:34 · answer #1 · answered by wildfreedom13 3 · 0⤊ 0⤋
Ok. The answer for A is 2.5/5 or 1/2. The answer for B is 6/8 or 3/4. The difference between the numerators in problem A is 1. 1/2 of 1 is 1/2 or 0.5. 2 and a half is one half of 5. The difference between the numerators in problem B is 2. 1/2 of 2 is 1. So you add 1 to 5 and it is 6. That makes the numerator 6 and the demoninator 8. 6/8 is equal to 3/4. Hope this helps.
2007-09-15 10:50:34 · answer #2 · answered by I love horses 3 · 0⤊ 0⤋
1/2 and 3/4 you need to find a common denminator that will work 2/5 =4/10 and 3/5 = 6/10 so the answer is easybetween them is 5/10 or 1/2. the second is easy the answer is 6/8 =3/4, so the answer is 3/4
2007-09-15 10:55:08 · answer #3 · answered by hipassgramps 1 · 0⤊ 0⤋
You simply average the two fractions.
Add them and divide by 2.
So 2/5 + 3/5 = 5/5 = 1
Answer is 1/2.
Similarly, the second one is 12/16 = 3/4
2007-09-15 10:50:40 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
1/2
3/4
2007-09-15 10:50:46 · answer #5 · answered by biged 3 · 0⤊ 0⤋