In order to solve this system of equations by substitution:
x + 2y = 9
3x - y = 13
Use the first equation and solve for x in terms of y:
x + 2y = 9
To do this, subtract 2y from both sides of the equation:
x + 2y = 9
= x + 2y - 2y = 9 - 2y
= x = 9 - 2y
Now, use this value, 9 - 2y, that equals x and substitue it into the second equation:
3x - y = 13
= 3(9 - 2y) - y = 13
Next, use the distributive property, which states that for numbers a, b, and c:
a(b + c) = ab + ac
a(b - c) = ab - ac
So:
3(9 - 2y) - y = 13
= 27 - 6y - y = 13
Combine like terms:
27 - 6y - y = 13
= 27 - 7y = 13
Subtract 27 from both sides of the equation:
27 - 7y = 13
= 27 - 7y - 27 = 13 - 27
= -7y = -14
Lastly, divide by -7 in order to solve for y:
-7y = -14
= -7y/-7 = -14/-7
= y = 2
Substitue this value of y into one of the original equations to solve for x and obtain your answer:
x + 2y = 9
= x + 2(2) = 9
= x + 4 = 9
= x = 5
This is your answer: x = 5 and y = 2, or in coordinate form (5, 2).
Hope this helps!
2007-09-15 10:41:29
·
answer #1
·
answered by zero_max12 2
·
0⤊
0⤋
No sweat, just solve equation 1...
x= 9-2y
and put in equation 2:
3(9-2y) -y =13
Clear the ( ), collect y and constant terms on opposite sides of the "="
Solve for y.
Insert in equation 2 (somewhat easier than 1) and find x.
Validate by doing same in equation 1.
2007-09-15 10:38:09
·
answer #2
·
answered by cattbarf 7
·
0⤊
0⤋
First guy: x = 9 - 2y
SUBSTITUTE this into the second guy:
3(9 - 2y) - y = 13
27 - 6y - y = 13
-7y = -14
y = 2
which means x + 4 = 9 or x = 5
2007-09-15 10:38:17
·
answer #3
·
answered by PMP 5
·
0⤊
0⤋
substitute 4x for y so: 4x = 3x - 3 then move the x's to the same side by subtracting 3 x from 4x so: x = -3
2016-05-20 05:09:10
·
answer #4
·
answered by ? 3
·
0⤊
0⤋
x=5
y=2
2007-09-15 10:36:26
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
y=2
x=5
You can sub those right back into the equation to check
2007-09-15 10:38:46
·
answer #6
·
answered by pyt_323 1
·
0⤊
0⤋