Kinematics... 2 dimensional?

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Kinematics... 2 dimensional?

AN OLYMPIC jumper leaves the ground at an angle of 23 degrees and travels through the air for a horizontal distance of 8.7m before landing. What is the take off speed of the jumper?

2007-09-15 10:17:29 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics

2 answers

You still might need time, but what I got was that he lieft with a velocity of 2.5097 m/s and it took him .3768 seconds before he fell back down on the ground, but these numbers dont make sence in my mind...

Oh well, thre you go!

2007-09-15 10:32:33 · answer #1 · answered by Anonymous · 0⤊ 0⤋

v0 = sqrt(range*g/sin(2theta) = 10.887 m/s
(See ref. for derivation of equation)

2007-09-15 18:41:12 · answer #2 · answered by kirchwey 7 · 0⤊ 0⤋