2007-09-15 07:32:33 · 31 answers · asked by Anonymous in Entertainment & Music ➔ Polls & Surveys
I have a few hehe! I ask this question alot!
2007-09-15 07:34:12 · update #1
um...i know one of my contacts....shes my gf.....and we're engaged......so i guess i would have to say its more than a crush
2007-09-15 07:50:02 · answer #1 · answered by Saren Arterius 5 · 0⤊ 0⤋
Yes
2007-09-15 14:37:49 · answer #2 · answered by ? 5 · 0⤊ 0⤋
I am here to formally DENY having a crush on Judas Rabbi. Yes, I may ask a lot of questions involving him but, hey, he has a lot of points and he often writes short, moronic answers.
Worst of all, he admits that he'd be willing to work for Yahoo.
2007-09-15 14:36:25 · answer #3 · answered by Anonymous · 1⤊ 0⤋
Yes, indeed. I have one crush in P&S (he knows about it) and another outside of P&S (he does not know).
Fyre & Reign (aka Fyre's Fury) has a crush on Judas Rabbi. The more she denies it, the more I am certain that the rumor is true.
2007-09-15 14:38:02 · answer #4 · answered by Anonymous · 1⤊ 0⤋
Yup. Two of my contacts. They should be the obvious ones once you look at them.
And yeah, you do ask this question a lot. But no worries!
^_^
2007-09-15 14:37:19 · answer #5 · answered by Hailey 3 · 1⤊ 0⤋
Yeah, One she left P & S last year and I havn't heard from her since but the search is on. I am still searching!
2007-09-15 14:35:52 · answer #6 · answered by Alexecution: Kickilution 5 · 1⤊ 0⤋
Tinkerbell and Teddy
2007-09-15 14:36:48 · answer #7 · answered by Anonymous · 2⤊ 0⤋
I'm engaged to be married to one. The wedding is on Sept. 27th.
2007-09-15 14:36:42 · answer #8 · answered by Miss T 7 · 1⤊ 0⤋
sure..and its more than a crush now,,leave your e-mail or cell number call u on the big day ,,lol
2007-09-15 14:43:07 · answer #9 · answered by reifguy 6 · 0⤊ 0⤋
Me tinks me alreddi ansad tis and gots best ansa.
I sorta do, I like someone at school too.
2007-09-15 14:38:29 · answer #10 · answered by Lt. Shinysides 6 · 0⤊ 1⤋
Yes but i wont say who
2007-09-15 14:35:46 · answer #11 · answered by Anonymous · 0⤊ 0⤋